1. 삼각 풀이 -1의 법칙 & 피타고라스 비교-

A높이1 B밑변1 C빗변√2

A, 1/√2=√0.5 → (1-√0.5²=0.5=√0.5)→√0.5/√0.5*1=1

A √2/1=√2 → (√2²=2)-1=1 → √1/√2*√2 =1

B 1/√2=√0.5 → (1-√0.5²=0.5=√0.5)→√0.5/√0.5*1=1

B √2/1=√2 → (√2*√2=2)-1=1 → √1/√2*√2 =1

C, (1/1)/((1/1)+(1/1)) = 1/√0.5 *1=√2

C, 1/√((1/1)/((1/1)+(1/1)))*1 = √2

A높이 9, B밑변12 C빗변15

A 9/15 =0.6 → (1-0.6²)→√0.64/0.6*9= 12

B 12/15 =0.8 → (1-0.8²)→√0.36/0.8*12=9

C (9/12)/ ((9/12 )+(12/9)) = 1/√0.36*9 = 15

C (12/9)/ ((9/12 )+(12/9)) = 1/√0.64*12 =15

-피타고라스-

a=√c²-√b² → √(c*c) -√(b*b)=√a

b= √c²-√a² → √(c*c)- √(a*a)=√b

c=√a²+√b² → √(a*a)+√(b*b)=√c

a1, b1, c√2

a=√(√2*√2=2)-√(1*1=1)=√1

b=√(√2*√2)-√(1*1)=√1

c=√(1*1)+√(1*1)=√2

a12, b9, c15

a 15²-9² → √(15*15=225) -√(9*9=81)→ √144 = 12

b 15²-12² → √(15*15=225)-√(12*12=144)→ √81= 9

c 9²+12² → √(9*9=81)+√(12*12=144)→√√225 =15